Problem #1.

1. A figure composed of congruent cubic blocks has four layers. On the lowest layer are 7 rows of 7 blocks each. Centered on the bottom layer are 5 rows of 5 blocks each. Centered on top of that are 3 rows of 3 blocks each. Finally, a central block is placed on top of the entire structure. See the picture below. After the blocks are placed, the entire figure is spray painted from the sides and top. How many blocks have 6 painted sides, how many have 5, 4, 3, 2, 1 and 0 painted sides? Suppose a similar figure has 99 rows of 99 blocks each on the bottom layer. How many have 6, 5, 4, 3, 2, 1 and 0 painted if the structure is built similar to the one shown?

 

Most students approached this from an analytical basis.  Starting with those that have no color

            0 painted sides – a pyramid with 5, 3, and 1 cubes or 25 + 9 +1 = 35

            1 painted side  - none of the cubes have one painted side            =   0

            2 painted sides – All the cubes along the edge and on the surface 4x5 + 4x3 + 4x1 = 36

            3 painted sides – All the corner surface cubes = 12

            4 painted sides – None = 0

            5 painted sides – The top cube = 1

            6 painted sides – None = 0

            Total cubes = 35 + 0 + 36 + 12 + 0 + 1 + 0 = 84 = 49 + 25 + 9 + 1

 

Problem # 2

2. Suppose that a regular octagon is filled as shown in the figure below. What is the area of the shaded region if each side of the octagon is 4 cm long?

The two right triangles that make up the shape have legs of 4 and (4 + 42).  Because there are two similar triangles, the total area would be 2 * 1/2 b * h or  2 * ½ * (4 + 42) * 4 or approximately 90.51

 

 

Problem #3

3. There are 10 lines in a plane each intersecting the other nine. No three lines pass through the same point. At how many points do the lines intersect, and into how many regions do they separate the plane?

Each is a mathematical progression shown in the table below

 

Lines

1

2

3

4

5

6

7

8

9

10

Regions

2

4

7

11

16

22

29

37

46

56

Intersections

0

1

3

6

10

15

21

28

36

45

 

The formula for finding the number of regions (given n lines) is:            0.5n2 + 0.5n + 1

The formula for finding the number of intersections (given n lines) is:   0.5n2 – 0.5n

 

Problem #4

4. Counting only paths that follow the lines and go downward or to the right, how many paths for A to D are possible?

 

 

Problem #5

5. A six pointed regular star consists of two interlocking equilateral triangles. What is the ratio of the area of the entire star to the area of one of the overlapping equilateral triangles?

The six pointed star is comprised of 12 small equilateral triangles.  One of the two equilateral triangles is comprised of 9 of the small ones.  Therefore the ratio of the entire star to one of the large equilateral triangles is 12/9 ot 4/3 or 1.3333…

 

Problem #6

6. Points A, B, C, and D lie on the same line, in the order written. If AB:AC = 1:3 and BC:CD = 4:1, compute the ratio AB:CD.

 

The following number line meets the requirements.  You will notice that AB:CD is a ratio of 2 to 1.

 

Problem #7

7. Two identical oil pipelines are circular cylinders of radius 6". The Environmental Protection Agency has ordered that they be replaced with a single pipeline with the same capacity. If the new pipeline is also a circular cylinder, what must the radius be?

The capacity of a pipe is measured by its cross sectional area.  The capacity of both 6” pipes is 2 * 36 * p  (A = pr2) or 72 p.

The cross sectional area of the single pipe must be the same or 72 p  must be equal to pr2  where r is the new radius.  Solving that problem will yield an r of  8.49 inches.

 

Problem #8

8. Each side of the small squares below is a toothpick. Cross out six toothpicks, so that there remain only two squares.

 

One possible solution is pictured below.  The red toothpicks have been removed.

 

Problem #9

9. Determine the largest number of boxes of dimension 2x2x3 that can be placed inside a box 3x4x5

 

Although the volumes have a ratio of 5 to 1, by trial and error you will find that only 4 of the smaller box can fit into the larger box.

 

Problem #10

10. In triangle ABC: AB = AC, angle A = 80°, CE = CD and BF = BD then angle EDF equals what measure?

 

 

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